A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of 238 graduating seniors and found the mean score to be 493 with a standard deviation of 97. Calculate the margin of error using the given formula. How could the results of the survey be made more accurate?

±12.323

Step-by-step explanation:

A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of 238 graduating seniors and found the mean score to be 493 with a standard deviation of 97. Calculate the margin of error using the given formula. How could the results of the survey be made more accurate?

The formula for margin of Error =

±z × Standard deviation/√n

We are not given the confidence interval but let us assume the confidence interval = 95%

Hence:

z score for 95% confidence interval = 1.96

Standard deviation = 97

n = random number of samples = 238

Margin of Error = ± 1.96 × 97/√238

Margin of Error = ±12.323

c

step-by-step explanation: