A rectangle has length 4 inches and width 2 inches. If the length and width of the rectangle are each reduced by 50 percent, by what percent will the area of the rectangle be reduced?

25%

Step-by-step explanation:

Given: A rectangle has length 4 inches and width 2 inches.

Area = Length x width

= 4 inches x  2 inches

= 8 square inches

If length is reduced by 50% , then length

If width is reduced by 50% , then length

Reduced area = (reduced length) x (reduced width)

= 2 inches x 1 inch

= 2 square inches

The percentage of the area of the rectangle be reduced :-

Hence, the percent of the area of the rectangle be reduced = 25%

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204