A particle is projected from a point O with speed V m/s and at an angle of elevation of x where x us tan =4/3 The point O is 42.5 m above a horizontal plane. The particle strikes the plane at point A , 5 seconds after it is projected. Find ;
1. The value of V
2. The distance between 0 and A

b i think

step-by-step explanation:

not really sure

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step-by-step explanation:

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for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: