River collects old coins. He has four less than twice as many rare nickels as
he does rare quarters. I the face value
of the coins is $3.65, Which system of
equations can be used to find n, the
number of nickels, and ç, the number of
quarters that he has?
a) 25n +59 = 365
29-4=n
b) 5n +59 = 3.65
49 +2=n
c) 5n + 256 = 365
29-4=
d) 5n + 259 = 365
49-2=n
e) 25n +59 = 365
49-2=n

9514 1404 393

  c) 5n +25q = 365

     2q -4 = n

Step-by-step explanation:

The number of nickels (n) is 4 less than twice the number of quarters (q), so one of the equations is ...

  2q -4 = n

The face value is 365 cents, so another equation is ...

  5n +25q = 365

These equations seem to match choice C.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

think about it deeply and passionately about this property

i am sorry