shasta claimed that the equation x^2+25=0 can be solved by using its factored form of (x+5i)^2=0, and that -5i is the only zero for this function. which statement is true?

The given equation will have two roots as +5i and -5i

Step-by-step explanation:

Shasta claimed that the equation x^2+25=0 can be solved by using its factored form of (x+5i)^2=0, and that -5i is the only zero for this function

The given equation is

This clearly shows it will have complex roots, and since it is a quadratic equation it will have 2 complex roots

x = ± 5i

It will be false to say that -5i will be the only complex root to this equation.

The given equation will have +5i and -5i as its roots.

Lets verify

x = +5i

x = -5i

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

step-by-step explanation: