Is this correct

16-2t=5t+9

yes it is t={1}

PREMISES

16–2t=5t+9

CALCULATIONS

16–2t=5t+9

(16–9)-(2t-2t)=5t+2t+(9–9)

7–0=7t+0

7t=7

7t/7=7/7

t=1/1

t=

1

PROOF

If t=1, then the equations

16–2t=5t+9

16–2(1)=5(1)+9

16–2=5+9 and

14=14 prove the root (zero) t=1 of the statement 16–2t=5t+9

Step-by-step explanation:

your answer is b ^w^ hope i

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )