Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = xe^−x^2/32, [−2, 8]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

, [ -2,8]

Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

Absolute maximum is a point where the function has its greatest possible value.

Absolute minimum is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

Using the product rule, first derivative will be:

= 0

x = ±4

x can't be -4 because it is not in the interval [-2,8].

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

b i think

step-by-step explanation:

not really sure

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3