(20 points and brainlest to whoever answers correctly!!!) PQ is formed by P(10,4 ) and Q(2,-8) of line k is the perpendicular bisector of PQ write a linear equation

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: (, )

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula:

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = (6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

answer: i believe c. is the answer sorry if i am wrong

step-by-step explanation:

can someone answer this question plz

step-by-step explanation: