Suppose M is the line with equation x=-5, line N is the line with equation y=1, line G is the line with equation y=x, and line H is the line with equation y=-2. Given A(9,-3), B(6,4), and C(-1,-5), what are the coordinates of the vertices of triangle A'B'C' for a reflection across line M?

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

he answer is x=1x3 because x=1 to x=3