Pls pls help me with this

Please check the explanation.

Step-by-step explanation:

                                                        6)

Given ΔMNO ≅ ΔPQR

As congruent parts of congruent triangle are congruent.

and also given

so

m∠N = m∠Q

2x+6 = 4x+12

4x-2x = 6-12

2x  = -12

Divide both sides by 2

x = -6

Thus, the value of x = -6

Therefore, option 'A' is true.

                                                     7)

Given ΔABC ≅ ΔDEF

As congruent parts of congruent triangle are congruent.

and also given

so

AB = DE

4v+2 = 6v-4

6v-4v = 2+4

2v=6

Divide both sides by 2

v = 3

Thus, the value of v = 3

Therefore, option 'A' is true.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

stop cheating

step-by-step explanation: