For what value of “a”are the graphs of 5y = -2x + 10 and 3y = aX- 15 parallel

a = -6/5

Step-by-step explanation:

For the graphs to be parallel the graphs should have same slope(m)

So we rewrite both our equations in the slope-intercept form then compare the slope to find the value of a like this,

This equation is the slope-intercept form we convert both our equations in this form firstly taking equation 1

so if we compare it with y = mx + b the coefficient of x is m and hence

m= -2/5 now solving for equation 2

so here if we compare it with y = mx + b the coeffienct of x is a/3 so since parallel lines have same slope by the formula:

we equation both the slope to each other to find the value of a like this,

so the value of a equals

a= -6/5

1. 34

2. 268

3. x=14.4

step-by-step explanation:

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]