Yall how do I find a common denominator? If the question is 3/4+2/3 would I multiply 3 by 3 and 2 by 4?? So if 3x3 is 9 and 2x4 is 8 do I add 9 and 8? So then 17 would be my commune denominator?

the common denominator is the number on the bottom of the fraction. in this case it would be 4 (in 3/4) and 3 (in 2/3), you have to find a number which equals the same for both! so 3 and 4 both go into 12. 3 × 4 and 4 × 3, so you common denominator is 12! but, you also have to multiple the same number up on the top number. so 3 × 3 and 2 × 4. Then you Add! but only the top numbers! you can only add/subtract fractions that have the same common denominator! your answer will end up being the improper fraction of 17/12. if you have to turn it into a decimal or make it proper, then do so ^^

to find a common denominator, you have to find the number which both numbers equally go into! so no decimals. check the times tables!

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.