Half of the product of two consecutive numbers is 105. to solve for n, the smaller of the two numbers, which equation can be used?

a.) n^2 + n – 210 = 0
b.) n^2 + n – 105 = 0
c.) 2n^2 + 2n + 210 = 0
d.) 2n^2 + 2n + 105 = 0

There are several information's already given in the question. Based on those information's the answer can be detrmined.
Smaller of the two integers = n
Larger of the two integers = n + 1
Then
(1/2) * [(n) * ( n + 1)] = 105
(1/2) * (n^2 + n) = 105
m^2 + n = 210
n^2 + n - 210 = 0
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the first option or option "A".

Sorry i didn’t know i had