A corner store sells two kinds of baked goods: cakes and pies. A cake costs $4 and a pie costs $6. In one day, the store sold 9 baked goods for a total of $44. How many cakes did they sell?

the number of cakes sell is 5

Step-by-step explanation:

The computation of the number of cakes sold is shown below;

Let us assume

The cake be C

And, the pie cost be P

Given that

There is two types of baked goods sold

The cost of the cake is $4

And, the cost of the pie cost is $64

Now the store sold 9 baked goods for a total of $44

So, the equation would be

C + P = 9

P = 9 - C (1)

4C + 6P = 44(2)

Now put the value of P in equation 2

4C + 6(9 - C) = 44

4C + 54  - 6C = 44

-2C = -10

C = 5

And, P = 4

hence, the number of cakes sell is 5

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).