The telephone company offers two billing plans for local calls. Plan 1 charges $30 per month for unlimited calls and Plan 2 charges $15 per month plus $0.04 per call. Use an inequality to find the number of monthly calls for which plan 1 is more economical than plan 2

Step-by-step explanation:

CHECK THE COMPLETE QUESTION

The telephone company offers two billing plans for local calls. Plan 1 charges $30 per month for unlimited calls and Plan 2 charges $15 per month plus $0.04 per call.

a. Use an inequality to find the number of monthly calls for which Plan 1 is more economical than Plan 2.

b. Explain the meaning of the answer to part

We can denote the number of calls as "y"

From plan 1, the Total monthly charge is $30

From plan 2, the Fix charge is $15 with $0.04 per call

We can expressed the cost of "y" call as( $0.04y)

From plan2, The monthly charge can be expressed as (0.04x + 15)

a. Use an inequality to find the number of monthly calls for which Plan 1 is more economical than Plan 2.

Here, Plan 1 is more economical than plan 2.

0.04y + 15 > 30

Collect like terms we have

0.04y > 30-15

0.04y> 15

y > 375

b) in case, more than 375 calls are made,then the economical plan is plan 1

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..