Aliquid vessel which is initially empty is in the form of an inverted regular hexagonal pyramid of altitude 25 feet and base edge 10 feet. by how much will the surface rise when 6,779 liters of water is added?

Step-by-step explanation:

A liquid vessel in the form of an inverted regular hexagonal pyramid.

Altitude of pyramid, h = 25 feet

Base edge of pyramid, a = 10 feet

A liquid vessel contain maximum volume

Change cubic foot to liter

A vessel fill 6,779 liters of water.

6779 lt = 239.398 ft³

Therefore,

Surface area rise, a = 10 ft , h = 2.764 ft

Hence, The surface rise when 6,779 liters of water is added to vessel will be 265.14 ft^2

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19