The school band collected $2,892 for 480 tickets sold to their spring concert. Adult tickets were $8 each and student tickets were $5 each. How many adult tickets were sold? Write and equation. This is an Algebra I question!!!

164 tickets

Step-by-step explanation:

We can denote number of adult tickets as "y"

Then if number of adult tickets is "y" then number of student tickets can be expressed as (480-y)

We were given Total cost of tickets as ($2892) eqn(1) and the cost of adult ticket is $8 per one, and also Cost student ticket $5 per one

the algebra equation can be expressed as :

8y + 5y= 2892

If we substitute eqn (1) we have

8y + 5(480 - y) = 2892

8a + 2400 - 5y = 2892

2892 - 2400= 8y-5y

492=3y

y = 164

Therefore, the number of adult tickets sold is 164

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.