Asix-sided fair die is rolled 4 times in a row. what is the probability of getting a 4 only on the last trial?

P = Number of ways of getting only 4 at the last trial / Total number of waysNumber of ways of getting only 4 at the last trial = 5 * 5 * 5 * 1 = 125 (for the first three trials, all but 4 is permissible (6 - 1 = 5 ways), and for the last trial, only 4 is permissible (1 way)).Total number of ways = 6 * 6 * 6 * 6 = 1296.P = 125/1296.

I hope my answer has come to your help. Thank you for posting your question here in .

The answer is “faster”.