How would you describe the relationship between the real zero(s) and x-intercept(s) of the function When you set the function equal to zero, the solution is x = 1; therefore, the graph has an x-intercept of (1, 0).
When you set the function equal to zero, the solutions are x = 0 or x = 1; therefore, the graph has x-intercepts at (0, 0) and (1, 0).
When you substitute x = 0 into the function, there is no solution; therefore, the graph will not have any x-intercepts.
Since there are asymptotes at x = –3, x = –1, and x = 0, the graph has no x-intercepts and, therefore, no real zeros.