Find the value of z in the isosceles triangle shown below.
V20
V20
8

Step-by-step explanation:

use Pythagorean theorem:

a² + b² = c²

where a = x

           b = 8/2 = 4  

           c = √20

plugin values into the formula:

x² + 4² = (√20)²

x² + 16 = 20

x² = 20 - 16

x = √4

x = 2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.