Given the following revenue and cost functions, find the x-value that makes revenue a maximum.
r(x)=76x-2x^2 ; c(x)=23x+91

P(x) that will be R(x) - C(x):

Note the use of parentheses! Without them we would not realize that both the 21 and the 98 should be subtracted.
Now that we have our profit function, we can see that:Its graph will be a parabola because of the squared term.The parabola will open downward because of the negative coefficient, -2, in front of the squared term.The highest point (which would be the maximum profit) on the downward parabola would be the vertex of the parabola.From the above we now know that we want to find the vertex of the profit parabola.

The x coordinate of the vertex of a parabola will be -b/2a where the "b" is the coefficient of the x term and the "a" is the coefficient of the x squared term. From p(x)= -2^2 + 34x-98

we can see that your "a" is -2 and your "b" is 34. So the x coordinate of the vertex (which is where the maximum profit is) will be: -34/-2=17

If you make you answer for clear i can answer it : )