A school carnival sold tickets to ride on a Ferris wheel. The charge was $3.00 for adults and $2.00 for students. If 54 tickets were sold for a total of $141.00, how many adult tickets were sold?

33 adult tickets and 21 student tickets

Step-by-step explanation:

We will create a system of equations.

Let x = the number of adult tickets sold and let y = the number of student tickets sold

x + y = 54

3x + 2y = 141

We can cancel out the y by multiplying the first equation by -2.

-2x - 2y = -108

3x + 2y = 141

Adding these equations together we get:

x = 33

Plugging this into the equation, we have:

38 + y = 54

y = 21

There were 33 adult tickets and 21 student tickets