The sum of the squares of two different numbers is less than or equal to 49. Twice one of the numbers squared is less than the other number. Which system of inequalities represents these criteria? Possible answers:
x^2 + y^2 ≤ 49 and 2x^2 < y
x^2 + y^2 ≥ 49 and 2x^2 < y
x^2 + y^2 ≤ 49 and x^2 < 2y
x^2 + y^2 ≥ 49 and x^2 < 2y

A. x2 + y2 ≤ 49 and 2x2 < y

Step-by-step explanation:

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1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

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