Which equation represents a line having a slope of 5
2
and a y-intercept of (0, –4)?
O A y = -x +4
O B. y= 42 -
A
o c. y= -40+
O D. 9= 3 – 4
5

2y - 5x = -8

Step-by-step explanation:

The standard equation of a line is expressed as y = mx+c

m is the slope

c is the y-intercept of the line

Given

Slope m = 5/2

Get the intercept c

Substitute m = 5/2 and the point (0, -4) into the expression y = mx+c

-4 = 5/2(0) + c

-4 = c

c = -4

Get the required equation;

y = 5/2 x - 4

Multiply through by 2;

2y = 5x - 8

2y - 5x = -8

This gives the required equation

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine