NO ONE IS HELPING ON THIS SITE, PLEASE HELP ME A scientist records the motion of a dolphin as it jumps from the water. The function`h\left(t\right)=-8t^{2}+32 t` models the dolphin’s height in feet above the water after t seconds. Show all work and explain your answers clearly. Use complete sentences.
What is the most reasonable domain for this situation? Explain your answer.

I don't know the answer but try using 900gle lens and scanning it on homework setting

Range is 0 ≤  h ≤ 32

Step-by-step explanation:

The height is a function of time and is described as h(t) = -8t² + 32t

h is the y-axis and t is the x axis, so we can write this as y = -8x² + 32 x.

This describes a parabola that opens downward, since the coefficient of the square term is negative. The maximum point for height will be at the vertex of the parabola.

y = ax² + bx + c

The x coordinate of the vertex is at -b/2a

a = -8, b = 32, c = 0

-b/2a = -32/-16 = 2

Maximum height is at x = 2 seconds (we can see this on the graph)

At 2 seconds, y = -8(2²) + 32(2) = -32 + 64 = 32

Again, we can see this on the graph.

The x intercepts are the points where y = 0

0 = -8x² + 32x = 8x(-x +4)

y will be 0 when x is 0 or 4 (confirmed by graph)

So, the height (y) = 0 at time (x) = 0 sec, 4 sec

0 ≤ y ≤ 32

y = h, so 0 ≤ h ≤ 32

I hope this helps.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles