The human cannonball is an act where a performer is launched through the air. The height of the performer can be modeled by h(x)=-0.004x^2+x+19h(x)=−0.004x^2+x +19, where ℎ is the height in feet and is the horizontal distance traveled in feet. The circus act is considering a flight path directly over the main tent. If the performer wants at least 5 ft of vertical height clearance, how tall can the tent be? Round your answer to the nearest foot.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

mean, 40.6

step-by-step explanation:

i cant answer this, theres no table. sorry man

step-by-step explanation:

i think the answer is a.( -3, -1 )