Jim has 3 pairs of pants
and 2 shirts. How many
different ways can he
dress?

12 different ways he can dress

Step-by-step explanation:

Let The Pant be A and Shirt be B

So, we have 3 pair of pants i.e., 6 Pants

Here, We assumed that the pant be A then 6 pants be

A₁ A₂ A₃ A₄ A₅ A₆

Now, For Shirts

We have 2 Shirts

But we assumed that the Shirt be B then 2 Shirts be

B₁ B₂

Then, We will make pair of A and B

A₁ = B₁

A₂ = B₁

A₃ = B₁

A₄ = B₁

A₅ = B₁

A₆ = B₁

A₁ = B₂

A₂ = B₂

A₃ = B₂

A₄ = B₂

A₅ = B₂

A₆ = B₂

Thus, 12 different ways he can dress

-TheUnknownScientist

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation:

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones