The mean June midday temperature in Desertville is 36C and the standard deviation is 3C. Assuming this data is normally distributed, how many days in June would you expect the middaytemperature to be between 39C and 42C

4

Step-by-step explanation:

Given that:

Mean temperature (m) = 36°C

Standard deviation (s) = 3°C

Temperature between 39°C and 42°C

Temperature < 39°

Probability of temperature < 39

P(x < 39)

The standardized score (Z) :

Z = (x - m) / s

Z = (39 - 36) / 3 = 1

p(Z < 1) = 0.84134 ( Z probability calculator)

Temperature < 42°

Probability of temperature < 42°

P(x < 42)

The standardized score (Z) :

Z = (x - m) / s

Z = (42 - 36) / 3 = 2

p(Z < 2) = 0.97725 ( Z probability calculator)

p(Z < 2) - p(Z < 1) = 0.97725 - 0.84134 = 0.13591

Hence, number of days in June = 30

Expected number of days = 30 * 0.13591 = 4.0773 = 4 (nearest whole number)

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )