Two dice are rolled; find the probability for total: a) 1, b) 4 or 6; c) <13

0 ; 2/9 ; 1

Step-by-step explanation:

In a roll of two dice ;

The sample space = (Number of faces on die)^number of dice rolled = 6^2 = 36

The total possible outcome = sample space = 36

The probability of an event (A) :

P(A) = number of required outcome / number of total possible outcomes

find the probability for total: a) 1,

P(total of 1)

Number of 1 total = 0

Hence, P(total of 1) = 0

b) 4 or 6;

Number of 4 total = 3

Number of 6 total = 5

3 /36 + 5 / 36 = 8/36 = 2/9

c) <13

P(total < 13)

Number of total < 13 = 36

36 / 36 = 1

i'm sure goog can you get that answer

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: