Write an equation in slope-intercept form that describes the line with a slope of -2 and (5,4) is on the line

The equation in slope-intercept form will be:

Step-by-step explanation:

Given

We know that the slope-intercept form of the line equation is

where m is the slope of the line and b is the y-intercept

substituting m = -2 and the point (5, 4) in the slope-intercept form to get the y-intercept 'b'

y = mx+b

4 = -2(5) + b

4 = -10 + b

b = 4+10

b = 14

now substituting m = -2 and b = 14  in the slope-intercept form to get the equation in slope-intercept

y = mx+b

y = -2x + 14

Therefore, the equation in slope-intercept form will be:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

step-by-step explanation:

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