Someone me in this question it is kind of confusing it is a question under pre calculus in first year calculus i will post the picture after this.. so the question is . the accompanying figure shows a rectangle inscribed in a isoceles right triangle whose hypotenuse is 2 units long.. a) express the y-coordinate of p in terms of x (you might start by writing and equation for the line ab). b) express the area of the rectangle in terms of x.

Neither P, nor A are on the sketch 
I guess P is the upper right corner of the rectangle 
and A=(0,1) 

P belongs to the line going through (1,0) and B(0,y) 
but we don't know the y-coordinate of B 

the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 
now look at the right triangle BOA 
his hypotenuse is AB=sqrt2 and the the kathete OA is 1 
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1 
so the coordinates of B are (0,1) 

the line going through (1,0) and (0,1) is L(x)=-x+1 

P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1) 

b) so if that's P, the height of the rectangle is -x+1 and the width=2x 
so its area A(x)=2x*(-x+1)= -2x²+2x 

I hope my answer has come to your help. Thank you for posting your question here in .

Where the white dots are is where your points should be plotted.a translation is simply just moving something from one place to another. in this case, you would move each plot point of the original shape 2 units up, and 5 units to the left.