The width of a rectangle is three more than twice the length. The perimeter is 96 inches. Find the length and the width.

The length of the rectangle is 15 inches and the width is 33 inches

Step-by-step explanation:

The dimensions for the rectangle are as follows:

L=L and W=2L+3

The equation for perimeter of a rectangle is:

P=2l+2w

To Solve:

1. Plug values into perimeter equation

96=2(L)+2(2L+3)

2. Simplify the equation above.

96=2L+4L+6

3. Combine like terms:

96=6L+6

4. Solve for L by subtracting 6 from both sides:

90=6L

5. Solve for L by dividing both sides by 6:

15=L.

6. Plug 15 into the equation for the width:

2(15)+3=w

30+3=w.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions