Company XYZ has created a neutral (useless) product to help college students make it to class on time. The company runs 40 studies with a confidence level of 95% Even if the product is useless, it would on average produce one study showing the
predict was beneficial, one study showing it was harmfut and thirty eight inconclusive studies (38 is 95% of 40) XYZ then
uses the one beneficial study to promote their new product.
Identity the misuse of statistical data by Company XYZ.
Loaded questions
Data manipulation
Overgeneralization
D
Discarding untavorable data
Ki

Discarding unfavorable data

Step-by-step explanation:

When companies discard data that will not support the narrative that they are trying to push, this is rightfully called, Discarding Unfavorable Data. There is a higher likelihood of this happening when the company does not publish all of the data the research showed.

Tobacco companies are an example of companies that do this. In cases where they hope to show that the relationship between cancer and tobacco smoking is minimal, they would show the very few examples that supports this.

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2