What is the expression and value of “six less than the quotient of a number and two, increased by ten” when n = 8? StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.
6 minus StartFraction n Over 2 EndFraction + 10; when n = 8, the value is 12.
StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 11.
6 minus StartFraction n Over 2 EndFraction + 10; when n = 8, the value is 9.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant

what "following statement"?

step-by-step explanation:

hi how are you doing today? if you ever need just tell me

step-by-step explanation: