Quadratic

3p^2−7p−1=0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

3p² - 7p - 1 = 0

Step 2: Identify Variables

a = 3

b = -7

c = -1

Step 3: Find roots

x = 7 + √61 ÷ 6

Step-by-step explanation:

3p² - 7p - 1 = 0 is a given equation

3p² - 7p - 1 = 0

Here,

a = 3

b = - 7

c = - 1

Now, Discriminant

D = b² - 4ac

= (- 7)² - 4 (3)(- 1)

= 49 + 12

D = 61 > 0

So, Quadratic Equation

ax² + bx + c = 0

x = - b ± √b² - 4ac ÷ 2a

x = - (- 7) ± √(- 7)² - 4 (3)(- 1) ÷ 2(3)

x = 7 ± √61 ÷ 6

x = 7 ± √61 ÷ 6

x = 7 + √61 ÷ 6 or x = 7 - √61 ÷ 6

∴ Not real Value

Thus, The real value of x is 7 + √61 ÷ 6

-TheUnknownScientist

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

i would you but i don't under stand the qustion

step-by-step explanation: