The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find the z-score thay correspondes to a lifespan of 2470 hours. A. 2.5 B.1.5 C.-1.5 D-2.4

C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula:

For X = 2470

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

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