He elimination method is ideal for solving this system of equations. By which number must you multiply the second equation to eliminate the y-variable, and what is the solution for this system? x + 3y = 42
2x − y = 14

A.
Multiply the second equation by -3. The solution is x = 12, y = 9.
B.
Multiply the second equation by -2. The solution is x = 12, y = 10.
C.
Multiply the second equation by 2. The solution is x = 15, y = 9.
D.
Multiply the second equation by 3. The solution is x = 12, y = 10.

D. Multiply the second equation by 3. The solution is x = 12, y = 10.

Step-by-step explanation:

First, look at the y variable of the first equation. It is 3y.

To solve by elimination, the variables have to add together to 0.

So, -3y needs to be added to -3y to eliminate the y variable.

The second equation has the y variable of -y, so it has to be multiplied by 3.

So, answer choice D is the correct answer.

    D. Multiply the second equation by 3. The solution is x = 12, y = 10.

x+3y=42

+3(2x−y=14)

7x=84

x=12 and since x+3y=42

12+3y=42

3y=30

y=10

So the solution is (12, 10)

Step-by-step explanation:

y + 11 = (1/4)(x + 16)

step-by-step explanation:

d 600 because 15*10*2=300

300+300=600

step-by-step explanation: