Using a directrix of y = 2 and a focus of (3, −4), what quadratic function is created? f(x) = one twelfth (x − 3)2 − 1 f(x) = −one sixth (x + 3)2 + 1 f(x) = one sixth (x − 3)2 + 1 f(x) = −one twelfth (x − 3)2 − 1