Edgar argues that reflecting the following image over the x -axis and then over the line y = x is the same as reflecting the same image over the
line y = -x. Prove whether Edgar is correct or not.
у
10
7
6
5
4
3
2
1
0
-6-5-4-3-2-1 0
-1
1
9
7
2
3
8
-10-9-8
10
-2
-3
-4
-5
-7
-8
-9
-10

 He is not correct. The resulting will be in a different quadrant.

Step-by-step explanation:  This would be much easier to answer with a screen shot of the image.

For example, if the original image is in quadrant 1, the first reflection over the x-axis places the new image in quadrant 4, "upside-down" and the second reflection over the y=x line places the new image in quadrant 2 and "oblique" to the original.

Reflecting the original over the y=-x line places the new image in quadrant 3.

c. 6tan80

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this