Someone can help me with this assignment about The Pythagorean Theorem. I have to solve it for the missing side length (s).

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .

6points possible: 3. total attempts: 5 for the data shown, answer the questions. round to 2 decimal places. x 7.3 11.7 21.7 18.8 23.2 20.7 29.7 21.2 10.6 find the mean: find the median: find the standard deviation:

A33.33 percent decrease followed by a 50% increase. greater or larger that original amount?