What is the statistical decision regarding the differences between the observed and expected frequencies if the critical value of chi-square is 9.488 and the computed value is 6.079

Fail to reject.

Step-by-step explanation:

For a goodness of fit test the decision rule is:

If the calculated value of the test statistic is more than the right tailed critical value of chi-square, then the null hypothesis will be rejected.

The hypothesis for a goodness of fit test is:

H₀: There is no differences between the observed and expected frequencies.

Hₐ: There is a significant differences between the observed and expected frequencies.

The computed value of the test statistic is, 6.079.

The critical value of chi-square is 9.488.

Calculated test statistic < Critical value

                            6.079 < 9.488

Thus, the null hypothesis was failed to rejected.

unpaid balance is : $149.99-$50 = $99.99 new balance = 149.99+2.62-50 = $102.61 finance charge = 99.99- 0.21/12= $1.75 new balance = 99.99+1.75 = $101.74 average daily balance method average daily balance= 3399.70/30 = $113.32 finance charge = $ 0.21/12ă—113.32 = $1.98 new balance = $149.99-50+1.98 = $101.97

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads