Suppose ΔDEF is the image of a translation of ΔABC. If D is at (−6, −2), what translation rule maps ΔABC to ΔDEF? The graph with X-coordinate marks -4, -2, 0, 2, 4 and Y-coordinate mark -4, -2, -1, 0, 2, 4. -The triangle ABC with coordinates A at (3, 0), B at (3, -2), C at (0, -3).

A. T⟨9, 2⟩(ΔABC) = ΔDEF
B. T⟨9, –2⟩(ΔABC) = ΔDEF
C. T⟨−9, 2⟩(ΔABC) = ΔDEF
D. T⟨–9, –2⟩(ΔABC) = ΔDEF

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

the answer is 3/2 and for decimal: 1.5

hope i

-lavira: )

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step-by-step explanation: