A yoga instructor offers two options for classes. Option 1: $40 joining fee and $20 per class Option 2$0 joining fee and $25 per class After how many classes will both options have the same cost?

The indifference point is 8 classes.

Step-by-step explanation:

Giving the following information:

Option 1:

$40 joining fee and $20 per class

Option 2:

$0 joining fee and $25 per class

First, we establish the total cost formulas:

Option 1= 40 + 20x

Option 2= 0 + 25x

x= number of classes

Now, we equal both formulas and isolate x:

40 + 20x = 25x

40=5x

8=x

The indifference point is 8 classes.

Prove:

Option 1= 40 + 20*8= $200

Option 2= 0 + 25*8= $200

michael scott & dwight schrute

step-by-step explanation:

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let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!