Use the coordinates of the labeled point to find the point-slope equation of the line.
(2, -1)
A. y-2=1/2(x+1)
B. y+ 1 = -2(x - 2)
C. y-1 = -2(x + 2)
D. y - 2 = 2(x + 1)

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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