Mathematics, 15.12.2020 21:00 zackmoore

What is 345 divied by 189 remander2

Answers: 1

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Answer from: dpranavesh446

4 remander

Step-by-step explanation:

Step 1:

Start by setting it up with the divisor 5 on the left side and the dividend 189 on the right side like this:

5⟌189

Step 2:

The divisor (5) goes into the first digit of the dividend (1), 0 time(s). Therefore, put 0 on top:

5⟌189

Step 3:

Multiply the divisor by the result in the previous step (5 x 0 = 0) and write that answer below the dividend.

5⟌189

Step 4:

Subtract the result in the previous step from the first digit of the dividend (1 - 0 = 1) and write the answer below.

5⟌189

-0

Step 5:

Move down the 2nd digit of the dividend (8) like this:

5⟌189

-0

Step 6:

The divisor (5) goes into the bottom number (18), 3 time(s). Therefore, put 3 on top:

5⟌189

-0

Step 7:

Multiply the divisor by the result in the previous step (5 x 3 = 15) and write that answer at the bottom:

5⟌189

-0

Step 8:

Subtract the result in the previous step from the number written above it. (18 - 15 = 3) and write the answer at the bottom.

5⟌189

-0

-15

Step 9:

Move down the last digit of the dividend (9) like this:

5⟌189

-0

-15

Step 10:

The divisor (5) goes into the bottom number (39), 7 time(s). Therefore put 7 on top:

037

5⟌189

-0

-15

Step 11:

Multiply the divisor by the result in the previous step (5 x 7 = 35) and write the answer at the bottom:

037

5⟌189

-0

-15

Step 12:

Subtract the result in the previous step from the number written above it. (39 - 35 = 4) and write the answer at the bottom.

037

5⟌189

-0

-15

- 35

You are done, because there are no more digits to move down from the dividend.

The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 189 divided by 5 calculated using Long Division is:

4 Remainder

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

Answer from: Quest

answer: $13,622.84

step-by-step explanation: check the picture for info and stats : )

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