If f(x) = x^3 – 10x^2 + 29x – 30 and f(6) = 0, then find all
of the zeros of f(x) algebraically.

Step 1: 1

(((x3) - (2•5x2)) + 29x) - 30 = 0

Step 2 2.1 x3-10x2+29x-30 is not a perfect cube

Step 3 Factoring: x3-10x2+29x-30

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 29x-30
Group 2: -10x2+x3

Pull out from each group separately :

Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)

Answer for 2: his profit would be $2.88 explanation: you have to first multiply 72 and 0.12 together to get $8.64 once you do that you know how much money the shopkeeper made from selling the candy bars individually. so you have to do 8.64-5.76=2.88 hope that ; )answer for 3: yeah i’m sorry i have no idea what number 3 is. i’m sorry i couldn’t with that.