2) What is the length of BD and BC in the diagram below? D(14.14)
C(11.10)
B (5.2)

please help me

BC is 10 unit

BD is 15 units

Step-by-step explanation:

Here, given the end points of the line segments, we want to calculate BD and DC

Mathematically, the distance between two points can be calculated using the formula;

D = √(x2-x1)^2 + (y2-y1)^2

For BD, we have the following

D = √(14-5)^2 + (14-2)^2

D = √(9)^2 + 12^2

D = √81 + 144

D = √(225)

Distance BD is 15 units

For BC, we have the following

D = √(11-5)^2 + (10-2)^2

D = √(6)^2 + 8^2

D = √100

D = 10

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

600,000,000,000, or 6e14

step-by-step explanation: