The relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8100 ft, the liquid boils at 203.66 degrees F. At an altitude of 4700 ft, the liquid boils at 208.42 degrees F. Write an equation giving the boiling point b of the liquid, in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2600 ft?

9514 1404 393

b = -0.0014a +215211.36 °F

Step-by-step explanation:

We are given two points: (a, b) = (8100, 203.66) and (4700, 208.42). We can use these in the 2-point form of the equation for a line

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1 . . . . . . line through (x1, y1) and (x2, y2)

Using the given values, we have ...

  b = (208.42 -203.66)/(4700 -8100)(a -8100) +203.66

  b = 4.76/-3400(a -8100) +203.66

  b = -0.0014a +215 . . . . . simplify

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At 2600 ft, the boiling point is ...

  b = -0.0014(2600) +215 = 211.36 °F

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )