The constraints of a problem are listed below. What are the vertices of the feasible region? 2x+3y2 12
5x+ 2y2 15
x20
y20
(3,0)
0 (0, 0), (0,4), (11:39)
110,19) (1996
(129) 3
O (0,0),
(6,0)
O (0,4),
(3, 0)
(15) (21 30)

Step-by-step explanation

The vertices of the feasible region are (0,0), (3,0), (1.5,2) and (0,2.5)

The constraints of the problem are given by,

Zero Test states that after substituting the point (0,0) in the inequalities,

If the result is true, then the solution region is towards the origin

If the result is false, then the solution region is away from the origin.

So, puttin g(0,) in the constraints gives,

implies 0 ≤ 15, which is true.

implies 0 ≥ 0, which is true.

implies 0 ≥ 0, which is true.

Thus, all the inequalities will have solution region towards the origin.

So, the feasible region is given as below.

Hence, the vertices of the feasible region are (0,0), (3,0), (1.5,2) and (0,2.5).

range is infinite on both x and y axis positive and negative

step-by-step explanation: