What is the equation of the line that passes through the point (-6,-6)and has a slope of -\frac{1}{3}− ?

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  y +6 = (-1/3)(x +6)

Step-by-step explanation:

Given a point and a slope, it is appropriate to use the point-slope form to represent the equation:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

For your point and slope, the equation is ...

  y -(-6) = -1/3(x -(-6))

  y +6 = -1/3(x +6)

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Of course, this can be rearranged to whatever form you need.

  y = -1/3x -8 . . . . slope-intercept form

  x +3y = -24 . . . . standard form

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

its an acute right triangle

step-by-step explanation: